Question

3tanA=2, (2sinA-cosA)/(2cosA-sinA)=?​

Answer 1

Answer:

hiii mate ur Ans is ....1/4

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..... hope it's helpful..

Answer 2

$wkt \\ \\ \frac{sina}{cosa} = tana \\ \\ given \: tana = \frac{2}{3} \\ \\ now \\ \\ \frac{2sina - cosa}{2cosa - sina} \\ \\ divide \: with \: cosa \\ \\ = \frac{2tana - 1}{2 - tana} \\ \\ = \frac{ \frac{4}{3} - 1}{2 - \frac{2}{3} } \\ \\ \frac{ \frac{1}{3} }{ \frac{4}{3} } \\ \\ = \frac{1}{4}$

hope it helps.