Question

Find the zeroes of the quadratic polynomial whose
product and sum of the zeroes are 23 and 10
respectively. And also find the polynomial.​

Answer 1

Sum of zeroes is 23

Product of zeroes is 10

ATQ

Putting the values in the general equation

K(x^2-x(alpha+bita)+alpha*bita)

Where k is any constant

K(x^2-x23+10)=0

Therefore the equation is x^2-x23+2

I hope that it is clear to you

Answer 2

Answer:

answer is

the polynomial is x^2-10x+23

the zeroes are 5+√2,5-√2

Step-by-step explanation:

firstly

the quadratic polynomial is ax^2+bx+c

let the zeroes be p,q, respectively

then

p+q=10

p(q)=23

so

p+q= -b/a

10= -b/a

p(q)=c/a

23=c/a

on comparing

a=1,b=-10,c=23

so polynomial will be

x^2-10x+23

zeroes will be

let x^2-10x+23=0

then applying quadratic formula

x=-b_+√4ac/2a

x=10-+√100-92/2

x=10+_√8/2

x=5+_√2

HOPE THIS WOULD BE HELPFUL