3tana.tanb=1 then prove that 2cos(a+b)=cos(a-b)
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given 3 tan a tanb=1
so, tan a tanb =1/3
change them in sin and cos
now sina sinb /cos a cos b=1/3
apply componendo and dividendo
use the forluae for cos(a+b) and cos (a-b). you will get your answer.
so, tan a tanb =1/3
change them in sin and cos
now sina sinb /cos a cos b=1/3
apply componendo and dividendo
use the forluae for cos(a+b) and cos (a-b). you will get your answer.
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