Question

3u^3-4u^2-12u+16 Factorise by factor theorem​

Answer 1

Answer:

3u^3-4u^2-12u+16

=3u^3-12u-4u^2+16

=3u(u^2-4)-4(u^2-4)

=(u^2-4)(3u-4)

={(u)^2-(2)^2}(3u-4)

=(u+2)(u-2)(3u-4)