Question

3u-5v+1=0, 2u-v+3=0 cross multiplication​

Answer 1

Answer:

2(3u−v)=5uv ....(1)

2(u+3v)=5uv ....(2)

From (1) and (2) we get

2(3u−v)=2(u+3v)

⇒3u−v=u+3v

⇒3u−u=3v+v

⇒2u=4v

⇒u=2v

Substitute u=2v in (1) we get

2(3×2v−v)=5×2v×v

⇒6v−v=5×v

2

⇒5v=5×v

2

⇒v=v

2

⇒v

2

−v=0

⇒v(v−1)=0

⇒v=0,v=1

Put v=0 in u=2v⇒u=0

∴u=0,v=0u=2,v=1

Answer 2

Step-by-step explanation:

3u=5v-1

u=(5v-1)/3

put value in sec. equation

2((5v-1)/3)-v+3=0

(10v-2)/3=v-3

10v-2=3v-9

10v-3v= -9+2

7v= -7

v= -1

so,

u=(5*(-1)-1)/3

u=(-5-1)/3

u= -6/3

u= -2