Math, asked by guttu4june2004, 2 months ago

(3x-1)²-(3x-2)(3x+1)​

Answers

Answered by vyavahareakash11
0

Answer:

(6x)(18x²-4)/~~~~<0. →x(3x+√2)(3x-√2)/(3x+ 1)²(3x+2)²<0. sign-digram solving : --(-2/3)- -(- √2/3)++(-1/3) ++(0)- -(√2/3) ++. solutions :.

Answered by dipakmandaltutu1973
0

Answer:

given: (3x - 1)^2 - (3x-2) (3x+1)

9x^2 -1 - 6x - ( 9x^2 + 3x - 6x -2)

-6x + 6x +1 - 3x + 2

3 - 3x ans

Step-by-step explanation:

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