Question

►8) A vehicle starts from rest attains a speed of 40m/s in a time interval of 10s. It moves with a constant velocity of 40m/s for 1 hr. and thereafter comes to rest in 20s. Calculate i) acceleration ii) retardation iii) total distance covered by vehicle during its motion.​

Answer 1

Answer:

Class 11

>>Physics

>>Motion in a Straight Line

>>Uniformly Accelerated Motion

>>A car starts from rest and ...

Question



A car starts from rest and accelerates uniformly for 10 s to a velocity of 8 ms−1. It then runs at a constant velocity and is finally brought to rest in 64 m with constant retardation. The total distance covered by the car is 584 m. Find the value of acceleration, retardation, and total time is taken.

Medium

Open in App

Solution



Verified by Toppr

(Refer to Image)

V=at

⇒8=a10

⇒a=0.8m/s2

V2=U2+2as

⇒U=82+2×a64

⇒a=2×64−64=−0.5m/s2

Distance travelled= Area of graph

⇒584=21×10×8+8×t1+21×16×8

⇒584=40+8t1+64

⇒8t1=480

⇒t1=60

Total time= 10+60+16=86s

Explanation:

hope it will help full for you