Question

(3x + 1) (2x + 3) = 3.​

Answer 1

=6x^2 + 9x + 2x + 3

= 6x^2 + 11x +3

By factorisation we get,

=6x^2 + 9x + 2x + 3 = 0

taking common

3x(2x+3)+1(2x+3)

(3x+1)(2x+3)=0

X=-1/3 or X= -3/2

thanks

Answer 2

Answer:

(3x + 1) (2x + 3) = 3

3x + 1 × 2x + 3 = 3

3x × 2x = 3 - 3 - 1

6x = -1

x = -1/6