Math, asked by reddykavitha09paqbgs, 11 months ago

3x+1/3=2-x solve equation

Answers

Answered by TRISHNADEVI
18
 \bold{ \underline{\red{SOLUTION \: \: }}}

 \bold{ \frac{3x + 1}{3} = 2 - x } \\ \\ \bold{ = > 3x + 1 = 3(2 - x)} \\ \\ \bold{ = > 3x + 1 = 6 - 3x} \\ \\ \bold{ = > 3x + 3x = 6 - 1} \\ \\ \bold{ = > 6x = 5} \\ \\ \bold{ = > x = \frac{5}{6} }

 \bold{ \underline{ \red{VERIFICATION\: \: }}}

 \boxed{ \bold{x = \frac{5}{6} }} \\ \\ \bold{L.H.S. = \frac{3x + 1}{3} } \\ \\ \bold{ = \frac{3 \times \frac{5}{6} + 1 }{3} } \\ \\ \bold{ = \frac{ \frac{5}{2} + 1 }{3} } \\ \\ \bold{ = \frac{ \frac{5 + 2}{2} }{3} } \\ \\ \bold{ = \frac{ \frac{7}{2} }{3} } \\ \\ \bold{ = \frac{7}{6} } \\ \\ \bold{Again ,} \\ \\ \bold{R.H.S. =2 - x } \\ \\ \bold{ = 2 - \frac{5}{6} } \\ \\ \bold{ = \frac{12 - 5}{6} } \\ \\ \bold{ = \frac{7}{6} }

 \bold{So,} \\ \\ \boxed{ \bold{L.H.S. = R.H.S.}}

 \bold{ \underline{ \red {ANSWER \: }}} \boxed{\boxed{\bold{ x = \frac{5}{6} }}}

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\red{\mathfrak{THANKS...}}

rakeshmohata: Awesome explanation sweetie❣❤
TRISHNADEVI: tq sir
rakeshmohata: =_= "
MrThakur14Dec2002: @ TRISHNADEVI yeah aapne last mai kya likha hai ......
TRISHNADEVI: Thanks
MrThakur14Dec2002: ur most welcome
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