Math, asked by Raghav3333, 1 year ago

(3x + 1)(3x+1)
Multiply these terms

Answers

Answered by Anonymous
9

Answer:



(3X+1)(3X+1) can be written as (a+b)^2

(a+b)^2 = a^2 + 2ab + b^2

Here,

a= 3x

b=1

(3x^2)+2×3x×1 + (1)^2

=9x^2+6x+1

Answered by nalinsingh
2

= (3x + 1) (3x + 1)

FORMULA :- (a+b)² = a² + b² + 2ab

Given,

a= 3x  ,  b=1  

=> 3x² + 2 × 3x × 1 + (1)²

> 9x² + 6x + 1

Similar questions