Question

(3x−1) is a factor of 3x3+17x2+18x−8.
Factorise 3x3+17x2+18x−8 completely.

Answer 1

Answer:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((3 • (x3)) - 17x2) + 18x) + 8 = 0

STEP

2

:

Equation at the end of step

2

:

((3x3 - 17x2) + 18x) + 8 = 0

STEP

3

:

Checking for a perfect cube

3.1 3x3-17x2+18x+8 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 3x3-17x2+18x+8

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 18x+8

Group 2: 3x3-17x2

Pull out from each group separately :

Group 1: (9x+4) • (2)

Group 2: (3x-17) • (x2)