(3x+1)x2+2(k+1)x+k=0. find the value of k for which the roots are real and equal.
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6x+2+2kx+2x+k=0
8x+2kx+k=0
8x+4kx-2kx+k=0
4x(2x+1) -k(2x+1)=0
(4x-k) (2x+1)=0
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