Question

3x^2+11x+10 find the roots

Answer 1

3x^2+11x+10=0
3x^2+6x+5x+10=0
3x(x+2) +5(x+2)=0
x+2=0    3x+5=0
x=-2,-5/3

Answer 2

Heya..!!

$3 {x }^{2} + 11x + 10 \\ = 3 {x}^{2} + (6 + 5)x + 10 \\ = 3 {x}^{2} + 6x + 5x + 10 \\ = 3x(x + 2) + 5(x + 2) \\ = (x + 2)(3x + 5)$
Therefore the roots are
$x + 2 = 0 \\ = > x = - 2 \\ and \\ 3x + 5 = 0 \\ = > 3x = - 5 \\ = > x = \frac{ - 5}{3}$
Hope it'll help.