3x^2-14x-5=0 by completing square method
Answers
Answered by
2
[tex]3 {x}^{2} - 14x - 5 = 0 \\ 3 {x}^{2} - 15x +1x - 5 = 0 \\ 3x(x - 5) + 1(x - 5) = 0 \\ (3x + 1)(x - 5)
Similar questions