Math, asked by poorvvak, 1 month ago

3x^2 - 14x - 5 =0. Solve the equation by factorisation method , D method and completing the square method.​

Answers

Answered by singhlovepreet32
2

SOLUTION

SOLUTIONWe have been given

SOLUTIONWe have been given3x2 - 14x - 5 = 0

SOLUTIONWe have been given3x2 - 14x - 5 = 03x2 - 15x + x - 5 = 0

SOLUTIONWe have been given3x2 - 14x - 5 = 03x2 - 15x + x - 5 = 03x(x - 5) + 1(x - 5) = 0

SOLUTIONWe have been given3x2 - 14x - 5 = 03x2 - 15x + x - 5 = 03x(x - 5) + 1(x - 5) = 0(3x + 1)(x - 5) = 0

SOLUTIONWe have been given3x2 - 14x - 5 = 03x2 - 15x + x - 5 = 03x(x - 5) + 1(x - 5) = 0(3x + 1)(x - 5) = 0Therefore,

3x + 1 = 0

3x + 1 = 03x = -1

3x + 1 = 03x = -1x = -1/3

3x + 1 = 03x = -1x = -1/3or,

3x + 1 = 03x = -1x = -1/3or,x - 5 = 0

3x + 1 = 03x = -1x = -1/3or,x - 5 = 0x = 5

3x + 1 = 03x = -1x = -1/3or,x - 5 = 0x = 5Hence, x = -1/3 or x = 5

3x + 1 = 0

3x + 1 = 03x = -1

3x + 1 = 03x = -1x = -1/3

3x + 1 = 03x = -1x = -1/3or,

3x + 1 = 03x = -1x = -1/3or,x - 5 = 0

3x + 1 = 03x = -1x = -1/3or,x - 5 = 0x = 5

3x + 1 = 03x = -1x = -1/3or,x - 5 = 0x = 5Hence, x = -1/3 or x = 5

Similar questions