Question

√3x-2=2√3+4 then the value of x

Answer 1

Step-by-step explanation:

$\sqrt{3x} - 2 = 2 \sqrt{3} + 4 \\ \\ \\ \sqrt{3x} = 2 \sqrt{ 3} + 6 \\ \\ \\ = > \sqrt{3x} = 2( \sqrt{3} + 3) \\ \\ = > x = \frac{4( \sqrt{3} + 3)^{2} }{ 3}$

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Answer 2

Answer:

The answer is -

Step-by-step explanation:

To find the value of x in $\sqrt{3}$x - 2 = 2$\sqrt{3}$ + 4

Follow the rules of linear equation

$\sqrt{3}$x - 2 = 2$\sqrt{3}$ + 4

$\sqrt{3}$x = 2$\sqrt{3}$ + 4 + 2

$\sqrt{3}$x = 2$\sqrt{3}$ + 6

x = $\frac{2\sqrt{3} + 6}{\sqrt{3}}$

  =  $\frac{2\sqrt{3}}{\sqrt{3}} + \frac{6}{\sqrt{3}}$

  = 2 + 2$\sqrt{3}$ (As 2$\sqrt{3}$ X $\sqrt{3}$ = 6)

x = 2 + 2$\sqrt{3}$

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