3x^2-29x+40=0
Solve this question by factorisation method
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use formula X = -b +- √b^2 - 4ac/2a
a =3 ,b = -29 ,c =40
X= -( -29)+-√{(-29)^2 - 4(3)(40)} / 2(3)
X = 29+-√ { 841 -480} / 6
X = 29+- √{361} / 6
X = 29 +- 19/6
= 29+19/6. , 29 - 19/6
X= 48/6 ,10/6
X = 8, 5/3
hence it's factors are ( x-8) ,(x- 5/3)
hope it helped !
thank you!
a =3 ,b = -29 ,c =40
X= -( -29)+-√{(-29)^2 - 4(3)(40)} / 2(3)
X = 29+-√ { 841 -480} / 6
X = 29+- √{361} / 6
X = 29 +- 19/6
= 29+19/6. , 29 - 19/6
X= 48/6 ,10/6
X = 8, 5/3
hence it's factors are ( x-8) ,(x- 5/3)
hope it helped !
thank you!
TheLostMonk:
x= 5/3 ,,,,,3x = 5 ,,3x -5 will be its second factor!
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