Question

find the remainder without division when 2x x cube minus 3 X square + 7 x minus 8 is divided by X - 1

Answer 1

p(x)=2x³-3x²+7x-8
g(x)=x-1
x-1=0
x=1 put in p(x)
2(1)³-3(1)²+7(1)-8
2-3+7-8
-2
so remainder is -2

Answer 2

$\textbf{ Hello Mate! }$

$p(x) = 2 {x}^{3} - 3 {x}^{2} + 7x - 8 \\ \\ now \: divisor \: is \: (x - 1) \\ x = 1 \\ \\ p(1) = 2 {(1)}^{3} - 3 {(1)}^{2} + 7(1) - 8 \\ p(1) = 2 - 3 + 7 - 8 \\ = - 2$

$\boxed{ Hence\:remainder\:is\:-2 }$

Have great future ahead!

$\textbf{ जय हिन्द! }$