(3x-2)(2x+3) - (3x-5)(x-1)
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the answer is 3x*x -3x+1
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=3x(2x+3)-2(2x+3)-3x(x-1)-5(x-1)
=(6x^2+9x-4x-6)-(3x^2+3x-5x+5)
=6x^2+5x-6-(3x^2-2x+5)
=6x^2+5x-6-3x^2+2x-5
=3x^2+7x-11
=(6x^2+9x-4x-6)-(3x^2+3x-5x+5)
=6x^2+5x-6-(3x^2-2x+5)
=6x^2+5x-6-3x^2+2x-5
=3x^2+7x-11
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