Question

3x-2(2x-5)=2(x+3)-8​

Answer 1

$\huge\tt\colorbox{lightgreen}{ANSWER}$

$3x - 2(2x - 5) = 2(x + 3) - 8$

$3x - 4x + 10 = 2x + 6 - 8$

$- x + 10 = 2x - 2$

$- x - 2x = - 2 - 10$

$- 3x = - 12$

$x = \frac{ - 12}{ - 3}$

$x = 4$

Answer 2

$\huge\mathtt{{\colorbox{silver} {ANSWER~}}}$

3x−2 (2x−5)=2(x+3)−8

3x - 4x + 10 = 2x + 6 - 83x−4x+10=2x+6−8

- x + 10 = 2x - 2−x+10=2x−2

- x - 2x = - 2 - 10−x−2x=−2−10

- 3x = - 12−3x=−12

x =$\frac{ - 12}{ - 3}$

x = 4