Question

3x^2 + (3p+1)x +(p+5) = 0 find value of p

Answer 1

Let the roots be x and x2.  

By product of roots

x3 = 1

x3 – 1 = 0

(x – 1)(x2  - x – 1) = 0

which implies x = 1 or x2 – x = -1

If we take x = 1 then by sum of roots p = -6 (but it is rejected as p > 0)

If we take  x2 – x = -1 then by e