Question

(3x^2_3x+4) (3_x)

what's the answer?​

Answer 1

Answer:

your answer

hope it will help you

Answer 2

$(3 {x}^{2} - 3x + 4) \times (3 - x) \\ \\ = 3(3 {x}^{2} - 3x + 4) - x(3 {x}^{2} - 3x + 4) \\ \\ = (9 {x}^{2} - 9x + 12) - 3 {x}^{3} + 3 {x}^{2} - 4x \\ \\ = \underline{ 9 {x}^{2}} - \underline{ \underline{9x}} + 12 - {3x}^{3} + \underline{ 3 {x}^{2}} - \underline{ \underline{4x}} \\ \\ = - 3 {x}^{3} + 12 {x}^{2} - 13x + 12 \\ \\ = 3 {x}^{3} - 12 {x}^{2} + 13x - 12$