3x^2-4x+7 find the zeros of this polynomial
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3x²-4x+7=0
Solution : 3x²-4x+7=0
=)3x²+3x-7x+7=0
=)3x(x+1)-7(x+1)=0
=)(x+1)(3x-7)=0
Either x+1=0 or 3x-7=0
x+1=0. or 3x-7=0
=)x=-1. =)3x=7
=)x=7/3
I hope that it is your question answered..
3x²-4x+7=0
Solution : 3x²-4x+7=0
=)3x²+3x-7x+7=0
=)3x(x+1)-7(x+1)=0
=)(x+1)(3x-7)=0
Either x+1=0 or 3x-7=0
x+1=0. or 3x-7=0
=)x=-1. =)3x=7
=)x=7/3
I hope that it is your question answered..
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