Math, asked by sandeepbartwal2643, 7 hours ago

(3x^2 + 5xy - 7y^2) + (11x^2 - 6xy + 2y^2)

Answers

Answered by shreekrishna35pdv8u8
1

Step-by-step explanation:

(3x^2 + 5xy - 7y^2) + (11x^2 - 6xy + 2y^2) \\  = 3x^2 + 5xy - 7y^2+ 11x^2 - 6xy + 2y^2 \\  = 14 {x}^{2}  - xy - 5 {y}^{2}

Answered by 6c2bhuvanakruthicbse
0

Answer:

(3x2+5xy−7y2)+(11x2−6xy+2y2)=3x2+5xy−7y2+11x2−6xy+2y2=14x2−xy−5y2

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