Math, asked by kiran206285, 1 year ago

3x/2 - 5y/3 = -2 this is equation number one and x/3+y/2= 13/6 by substistion method

Answers

Answered by Anonymous
4
\huge\mathcal{Answer \ :-}

\mathsf{Given \ equations \ :-}

 \frac{3x}{2}  -  \frac{5y}{3}  =  - 2 \\  \\
\mathsf{On \ further \ solving, \ we \ get}

 \frac{(3x)(3) - (5y)(2)}{6}  =  - 2 \\  \\  \frac{9x - 10y}{6}  =  - 2 \\  \\  9x - 10y =  - 12

\mathsf{Another \ equation}

 \frac{x}{3}  +  \frac{y}{2}  =  \frac{13}{6}  \\  \\
\mathsf{On \ further \ solving, \ we \ get}

 \frac{(x)(2) + (y)(3)}{6}  =  \frac{13}{6}  \\  \\  \frac{2x + 3y}{6}  =  \frac{13}{6}  \\  \\ 2x + 3y = 13

\mathsf{We \ get \ two \ equations}

\mathsf\red{9x - 10y \ = \ -12} ____(1)

\mathsf{And}

\mathsf\red{2x + 3y \ = \ 13} ____(2)

\mathsf{From \ (2), \ we \ get}

x =  \frac{13 - 3y}{2 }  \\  \\

\mathsf{Put \ this \ in \ (1), \ we \ get}

9( \frac{13 - 3y}{2} ) - 10y =  - 12 \\  \\  \frac{117 - 27y}{2}  - 10y =  - 12 \\  \\  \frac{117 - 27y - 20y}{2}  =  - 12 \\  \\ 117 - 47y =  - 24 \\  \\  - 47y =  - 24 - 117 \\  \\  - 47y =  - 141 \\  \\  y = 3

\mathsf{Now,}

x =  \frac{13 - 3y}{2 }  \\  \\

\mathsf{Putting \ y \ = \ 3}

x =  \frac{13 - 3(3)}{2}  \\  \\ x =  \frac{13 - 9}{2}  \\  \\ x =  \frac{4}{2}  \\  \\ x = 2

\mathsf\red{x \ = \ 2 \ And \ y \ = \ 3.}

\huge\mathbb{Hope \ this \ helps.}
Answered by rahulyadev2008
2

taking lcm of the eqution 1 = (9x-10y)/6=-2

       =9x-10y = -12

       = 9 x - 10 y + 12 = 0

   =   (2 x +3 y )/ 6 = 13/ 6  equation ...2

   = 2x +3y -13 =0

    find value of x from equation 1

         x =( -12+10y)/9

 put value of x in equation 2

2 (-12 + 10 y ) /9 +3y -13 = 0

(-24+20 y ) /9 + 3y - 13 =0

taking l c m of full eq..

-24 +20y + 27y -117= 0

47 y = 141

y = 3

put value of y in eq... 1

9 x -30 + 12 = 0

9 x = 18

x = 2  hope it help you

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