Question

3x^2-(6+2√3)x+4√3=0

Answer 1

Hello Mate here is your answer below,

$3x {}^{2} - (6 + 2 \sqrt{3} )x + 4 \sqrt{3} = 0 \\ = > 3x {}^{2} - 6x - 2 \sqrt{3} x + 4 \sqrt{3} = 0 \\ = > 3x(x - 2) - 2 \sqrt{3} (x - 2) = 0 \\ = > (3x - 2 \sqrt{3} )(x - 2) = 0 \\ = > 3x - 2 \sqrt{3} = 0 \\ = > 3x = 2 \sqrt{3} \\ = > x = \frac{2 \sqrt{3} }{3} \\ \\ or \\ \\ = > x - 2 = 0 \\ = > x = 2$

I hope that helps you

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