Question

3x 2.6y = 16
x + 5.2y=27
Solve the pairs of
Simultaneus
equation. Help me please​

Answer 1

Answer:

Here you go.....................................................

Answer 2

The question is we have to solve the pairs of simultaneous equations.

The given pair of equations is

$3x + 2.6y = 16 - - - 1\\ x + 5.2y = 27 - - - 2$

The above equations are the simultaneous equations

Simultaneous equations are a set of equations or a system of the equation also known as a system equation is a finite set of equation where a common solution is obtained

We can solve the given pair of equations by an elimination method.

Multiply the equation 2 by digit 3.

$3x + 15.6y = 81 - - - - - 3$

subtract equation 1 from equation 3 we get

$(3x + 15.6y = 81) - (3x + 2.6y = 16) \\ 13y = 65$

The value of y can be obtained by the division method.

$y = \frac{65}{13} = 5$

substitute the value of y in equation 1 we get,

$x + 5.2(5) = 27$

solve by normal mathematical addition and subtraction, we get

$x + 26 = 27$

Then the value becomes

$x = 27 - 26 = 1$

Therefore, the value of x is 1 and y is 5.

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