Question

3x+2/7+4(x+1)/5=2/3(2x+1)
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Answer 1

$\frac{3x + \frac{2}{7} + 4(x + 1)}{ 5} = \frac{2}{3} (2x + 1)$

$\frac{ \frac{3x}{1} + \frac{2}{7} + 4x + 4 }{5} = \frac{2}{3} \frac{(2x + 1)}{(1 + 1)}$

$\frac{ \frac{5x}{8} + 8x}{5} = \frac{(4x + 2)}{(3 + 3)}$

$\frac{ \frac{5x}{8} + \frac{8x}{1} }{5} = \frac{6x}{6}$

$\frac{ \frac{13 x {}^{2} }{9} }{5} = 3x$

$5 = 3x \times \frac{13 {x}^{2} }{9}$

$5 = \frac{3x}{1} \times \frac{13 {x}^{2} }{9}$

$5 = \frac{39 {x}^{3} }{9}$

$\frac{5}{1} \times \frac{39 {x}^{3} }{9}$

$\frac{195 {x}^{3} }{9}$

$= 21.6666666667{x}^{3}$