3x+2(x+2)=20-(2x-5)
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3x+2( x+2)=20-(2x-5)
in lhs multiply 2 from brackets and in rhs - from bracket
that is 3x + 2x+4=20-2x+5
then solve both the side
5x + 4 = 25- 2x
then shift the 2x from lhs to rhs and 4 to rhs
after that,equ is 5x + 2x = 25 - 4
7x = 21
shift 7 in denomator
x= 21/7
x = 3
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