The area of equilateral triangle whose altitude is
5✓3 cm is
PLEASE SOLVE IN NOTEBOOK WITH DIAGRAM SO I MAKE YOU BRAINLIST
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We know that in an equilateral triangle, all angles are equal to =600 and the altitude bisects the opposite angle.
Hence, follow the steps given below to construct the triangle.
1. Draw a line PQ and mark a point D on it.
2. Construct a perpendicular of length DA=5cm to PQ at point D
3. Construct ∠DAR=2600=300 to intersect PQ at B
4. Measure BD and cut off an arc on PQ of same distance DC on the other side of D
5. Join A to C
6. ABC is the required equilateral triangle.
On measuring the length of the sides, we get side length as 5.8 cm
∴ Area of triangle =21×5.8×5=14.5 cm2
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