3x-(2x-y)+(x-2y)-(x-y)
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\left[x \right] = \left[ 0\right][x]=[0] totally answer
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=3x-2x-(-y)+x-2y-x-(-y)
=3x-2x+y+x-2y-x+y
=3x-2x+x-x+y-2y+y
=x+0y
=x
=3x-2x+y+x-2y-x+y
=3x-2x+x-x+y-2y+y
=x+0y
=x
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