Math, asked by tanishaangari, 1 year ago

find the value of k, for which one root of the quadratic equation kx2 (root) - 14x+ 8=0 is 2

Answers

Answered by priyasinghal

Hope it helps u......

Attachments:

tanishaangari: u did this by own or copied from smwhere??

tanishaangari: usually for how much marks this question comes

tanishaangari: ???

tanishaangari: tysm

kiranbastwad0077: wrong answer

chauhandiwan: this is a wrong answer you have written 4 instead of 14

Answered by sherafgan354

Answer:

k = 5

Step-by-step explanation:

We are given the following quadratic equation

kx² -14x + 8 = 0

We have to find value of k, if one root of the equation is 2

As we know the root is any value of x that satisfies the above equation.

So, taking

x =2

substitute x =2 into above equation

k(2)² -14(2) + 8 = 0

k(4) - 28 + 8 = 0

4k -28 + 8 = 0

4k - 20 = 0

4k = 20

k = 20÷4

k =5

So, our desired value of k is 5

Previous Question

Next Question