Question

3x+2y=11;2x-3y+10=0 . find the value of xand y using method of elimination by substitution

Answer 1

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Answer 2

Answer:

3x + 2y =11

2x - 3y = -10

Multiply two in equatrion 1 and three in equation 2.

We will get

6x + 4y = 22

6x - 9y = -30

Subtract both the equations

6x - 6x + 4y + 9y = 22+30

13 y = 52

y = 52/13 = 4

Put the value of y in equation 1 .

3x + 2y = 11

3x + 2 * 4 = 11

3x + 8 = 11

3x = 11 - 8

3x = 3

x= 3/3 = 1