3x+2y=12
x-3y= -7
by substitution method
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3x+2y=12 eq.(1)
x-3y=-7 eq.(2)
x= 3y+7 eq.(3), substitute in (1)
3(3y-7)+2y=12
9y-21+2y=12
11y=33
y=3 substitute in (3)
x=16.
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Answered by
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Answer:
3x+2y=12-(1)
x-3y=-7-(2)
(1)*1-(2)*3
3x+2y=12
-
3x-9y=-21
_________
11y=33
__________
y=3
then
substitute y=3 in (1) or (2)
then
x-3(3)=-7
x-9=-7
x=-7+9
x=2
x=2, y=3. are the values
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