Question

3x + 2y=29 ; 5x-y =18

Answer 1

multiply 5 in equation (1) & 3 in equation (2)

(3x +2y = 29) × 5 --------(1)
(5x -y = 18) × 3-----------(2)
___________

15x +10y = 145
15x -3y = 54
- + -
____________ Now substract
13y =91
y =91/13
y = 7

put the value of y in equation

3x + 2× 7 =29
3x + 14 = 29
3x = 29 -14
3x = 15
3x = 15/3

X = 5 ANS

Hope it's helpful ✌

Answer 2

The question should be

Q) Find 'x' and 'y' by solving the two equations 3x+2y = 29, 5x-y = 18

Sol:

Given,

$3x+2y=29 ---- > (1)\\5x-y=18 ----- > (2)$

now, we have to solve the both equations

From equation (1)

$3x=29-2y\\x =\frac{29-2y}{3}$

Substitute 'x' in equation (2) we get

$5(\frac{29-2y}{3})-y=18$

multiplying both sides with '3', we get

$5(29-2y)-3y=54\\145-10y-3y=54\\13y=145-54=91\\y=\frac{91}{13}\\ y = 7$

Now, put 'y' in equation (1) we get

$3x+(2*7)=29\\3x=29-14\\ x=\frac{15}{3}\\ x=5$

∴ The values of $(x,y)$ are $(5,7)$

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