(3x+2y-4) (x-y+12)
solve the equation
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2
Answer:
(3x+2y-4) (x-y+12)
= 3x^2 - 3xy + 36x + 2xy - 2y^2 + 24y - 4x + 4y - 48
= 3x^2 - xy + 32x - 2y^2 + 28y - 48
Hope it helps you :)
Answered by
1
Answer:
3x2 - 32x -xy -y2 +28y -48
hope it helps!
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