Question

3x-2y=5/2 ; 1/3x + 3y = -4/3. Solve using Cranmer's method. Please Provide explanation.

Answer 1

Equations are

3x - 2y = 5/2 , 1/3 x + 3y = -4/3

or we can write

6x - 4y = 5 , x + 9y = -4

Using Cramer's rule to find the values of x and y, there are 3 different values that we need to calculate, they are D, Dx, and Dy. In all 3 cases the “D” stands for the determinant

D = Determinant of x and y values in 2 x 2 matrix

x = Dx/D and y = Dy/D, here we replace x and y values with the values after the equal sign respectively

So we have,

D = [ 6   -4
         1   9 ]

So D = (6)(9) - (-4)(1) = 58

Dx = [ 5   -4
          -4   9 ]

So Dx = (5)(9) - (-4)(-4) = 29

Dy = [ 6   5
          1  -4 ]

So Dy = (6)(-4) - (5)(1) = -29

Putting these values in our rule we get

x = 29/58 = 1/2

y = -29/58 = -1/2

Answer 2

Answer:

Step-by-step explanation: