Math, asked by pratikvikasbhagat833, 5 months ago

3x-2y=6 आणि 2x+y=11 ही एक सामायिक समीकरणे सोडवताना निश्चयक डी ची किंमत काढा?​

Answers

Answered by shambhaviborkar
12

Answer:

3x-2y=6--------equation 1

2x+y=11----------equation2

multiple equation 2. by 2

2×2+2×y=11×2

4x+2y=22--------equation3

subtract equation 1and 2

4x+2y=22

+ 3x -2y=6

---------------------

x. =16

x=16

substituting equation 1 by x=16

3(16)-2y=6

42-2y=6

42-6=2y

36=2y

36/2 =y

18=y

for cross check

do 3(16)-2(18)

42-36

= 6

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