Question

3x+2y-8=0 &5x-4y=6 graph

Answer 1

Answer:

First, you have to isolate by the x.

$\displaystyle 3x-2y=83x−2y=8</p><p>$

Add 2y from both sides.

$\displaystyle 2x-2y+2y=8+2y2x−2y+2y=8+2y$

Solve.

$</p><p>\displaystyle 3x=8+2y3x=8+2y$

Secondly, divide by 3 from both sides.

$</p><p>\displaystyle \frac{3x}{3}=\frac{8}{3}+\frac{2y}{3} </p><p>3</p><p>3x$

Solve.

$\displaystyle x=\frac{8+2y}{3}x= </p><p>3</p><p>8+2y</p><p>$

You have to subsititute by the x=8+2y/3.

$\displaystyle 5*\frac{8+2y}{3}+4y=65∗ </p><p>3</p><p>8+2y</p><p> </p><p> +4y=6$

Next, isolate by the y.

$\displaystyle 5*\frac{8+2y}{3}+4y=6=\boxed{ y=-1}5∗ </p><p>3</p><p>8+2y \\ </p><p> </p><p> +4y=6= </p><p>y=−1</p><p>$

Solve by y=-1.

$\displaystyle x=\frac{8+2(-1)}{3}x= </p><p>3</p><p>8+2(−1) \\ </p><p> </p><p> </p><p></p><p>\displaystyle 2*1=22∗1=2 \\ </p><p></p><p>\displaystyle 8-2=68−2=6$

Then, you divide the numbers from left to right.

$\displaystyle \frac{6}{3} </p><p>3</p><p>6 \\ </p><p> </p><p> </p><p></p><p>\displaystyle 6\div3=\boxed{2}6÷3= </p><p>2 \\ </p><p> </p><p> </p><p></p><p>\large\boxed{x=2, y=-1} </p><p>x=2,y=−1 \\ </p><p> </p><p>$

Therefore, the final answer is y=-1, and x=2.