Question

3x
3
6
9
3x
1
If
+
then integrals
dx is equal to
(x-1)(x-2)(x-3)
(x-1)(x-2)(x-3)
2 (x-1)
(x-2)
2 (x-3)​

Answer 1

Answer:

Integration goes the other way: the integral (or antiderivative) of 1/x should be a function whose derivative is 1/x. As we just saw, this is ln(x). However, if x is negative then ln(x) is undefined! The solution is quite simple: the antiderivative of 1/x is ln(|x|).

Step-by-step explanation:

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