Question

3x-3y=4 and 2x-6y=5 by cross multiplication​

Answer 1

ok buddy

this is your answer

the cross multiplication method states that

x/(b1c2-b2c1)=-y/(a1c2-a2c1)=1/(a1b2-a2b1)

so in this question,

eq1-   3x-3y=4

eq2-   2x-6y=5

then a1=3,    a2=2

         b1=-3,   b2=-6

         c1=4,   c2=5

putting values we get,

x/(-15+24)=-y/(15-8)=1/(-18+6)

=x/9=-y/7=1/-12

solving this we get

x=3/4

y=-7/12

HOPE IT HELPS BUDDY

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