Question

3x - 3y
6. If log(x + y) = log
2
then log x-log y =
1) log 5
2) log 10-log 2
3) log 3 + log 2
3
4) log
log, 8
2​

Answer 1

Answer:

log 5

Step-by-step explanation:

the question can be rewritten as:

log(x+y)=log(3/2) + log(x-y)

log((x+y)/(x-y))=log(3/2)

(x+y)/(x-y)=3/2

solving this we get

x=5y

so logx - logy = log5y - logy = log5