Question

3x+4y=1 and xy= 6 find the value of 27x³+64y³​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

(a+b)³ = a³+ b³ + 3ab(a+b)

(3x + 4y)³ = (3x)³ + (4y)³ + 3(3x)(4y)(3x+4y)

(1)³ = 27x³+64y³ + 3(3x)(4y)(1)

(1)³ =27x³+64y³ + 36xy

(1)³ = 27x³+64y³ + 36(6)

(1)³. = 27x³+64y³ +216

27x³+64y³ = 1 - 216

27x³+64y³ = -125

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