Question

3x-4y=10;4x+3y=5 plz solve this simultaneous equation

Answer 1

heya friend

here is your answer

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let,

3x-4y = 10 ----------> {1}

4x+3y = 5 ------------> {2}

{1} × 3 = 9x - 12y = 30

{2} ×4 = 16x + 12y = 20
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= 25x = 50

x = 50/25

x = 2

therefore , x = 2

now place x in eq 1

(3×2) - 4y = 10

6 - 4y = 10

-4y = 4

y = (-1)


sho ,

x = 2
y = (-1)


i hope it helped uh !!

thanks

Answer 2

Hi.

Here is your answer---

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Solving the Equation by Substitution methods.

Given Equations---

 3x -  4y = 10 
 3x = 10 +4y
  x =(10 + 4y)/3 ------------------------------eq(i)

4x + 3y = 5 -------------------------------eq(ii)

Putting the eq(i) in eq(ii),

4[(10 + 4y)/3} + 3y =5
  (40 + 16y)/3 + 3y = 5
 40 + 16y + 9y = 15          [Taking L.C.M.]
 40 + 25y =15
    25y = 15 - 40
        y =-1

Thus, putting y =-1 in eq(ii),

 4x + 3(-1) = 5
 4x - 3 = 5
 4x = 5 + 3
   x = 8/4
   x = 2

Thus the values of x is 2 and y is -1.

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Hope it helps.

Have a nice day.