3x-4y=10
4x+3y=5
Solve by Substitution Method
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here
3x-4y= 10
thus, 3x=10+4y
thus, x=10+4y/3
4(10+4y/3) +3y = 5
thus, 40+16y/3 + 3y=5
thus, 40+16y+3y=5×3
thus,40 + 19y=15
19y= -25
y= -25/19
put the value of y in equation one
3x -4(-25/19) = 10
3x +100/19= 10
3x = 10 - 100/19
3x = 190/19 - 100/19
3x = 90/19
x = 90/19 × 3
x= 270/19
x = 14. _________ since 270 ÷ 19 = 14.21 = 14
thus, (x,y) = (14,-25/19)
3x-4y= 10
thus, 3x=10+4y
thus, x=10+4y/3
4(10+4y/3) +3y = 5
thus, 40+16y/3 + 3y=5
thus, 40+16y+3y=5×3
thus,40 + 19y=15
19y= -25
y= -25/19
put the value of y in equation one
3x -4(-25/19) = 10
3x +100/19= 10
3x = 10 - 100/19
3x = 190/19 - 100/19
3x = 90/19
x = 90/19 × 3
x= 270/19
x = 14. _________ since 270 ÷ 19 = 14.21 = 14
thus, (x,y) = (14,-25/19)
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lebazir2004:
The Question has asked *SUBSTITUTION METHOD*
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