3x-4y=10 and 4x+3y=5 solve it by substitution
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Answered by
4
Answer:
3x-4y=10
3x= 10+4y
x= (10+4y)/3
by putting the value in other equation.
4x+3y= 5
4{(10+4y)/3}+3y= 5
40+16y+3y= 5
40+19y= 5
19y= -35
y= -35/19.
by putting the value in equation 1.
3x-4y= 10
3x-4(-35/19)= 10
3x+140/19= 10
3x= 10-(140/19)
3x= (190-140)/19
3x= 50/19
x= (50/19)*1/3
x= 50/57
therefore x= 50/57 and y= -35/19.
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Answered by
4
Answer:
X=2 and y=-1
Step-by-step explanation:
hope it helps
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