Question

3x + 4y = 12
Find two solutions for the given equation.

Answer 1

1) ..
put y=0 in given equation
3x+0=12
x=4

2)....
now put x=2 in equation
3x2+4y=12
4y=12-6
4y=6
y=3/2

Answer 2

Given Linear equation in two variables

3x + 4y = 12 ----( 1 )

i ) Substitute x = 0 , in equation ( 1 ) ,

3 × 0 + 4y = 12

=> 4y = 12

=> y = 12/4

y = 3

Therefore ,

( x , y ) = ( 0 , 3 )

ii ) Substitute y = 0 in equation ( 1 ) ,

3x + 4 × 0 = 12

=> 3x = 12

=> x = 12/3

x = 4

Therefore ,

( x , y ) = ( 4 , 0 )

Required two solutions are ( 0 , 3 ) ,

( 4 , 0 )

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