Question

3x-4y=12 put xas a 0
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Answer 1

x=0

3x-4y=12

then putting x=0

3(0)-4y=12

-4y=12

y=-3

hopes

Helps

Answer 2

$\huge \mathfrak \blue{hello \: friend}$

3x-4y=12

On putting x=0,

3(0)-4y=12

0-4y=12

-4y=12

-y=3

y=-3