Question

3x-4y÷2=10 , 3x+2y÷4 = 2​

Answer 1

i)

$\frac{3x - 4y}{2} = 10 \\ 3x - 4y = 20 \\ 3x = 20 + 4y \\ x = \frac{20 + 4y}{3}$

$\frac{3x + 2y}{4} = 2 \\ 3x + 2y = 8 \\ 3 \times \frac{20 + 4y}{3} + 2y = 8 \\ 20 + 4y + 2y = 8 \\ 20 + 6y = 8 \\ 6y = 8 - 20 \\ 6y = - 12 \\ y = - 2$

$x = \frac{20 + 4y}{3} \\ \frac{20 - 8}{3} \\ \frac{ - 12}{3} \\ - 4$