3x+4y=30,x+2y=12 by elimination method
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Answer:
x=6; y=3
Step-by-step explanation:
Given:
3x+4y = 30.........equation (1)
x+ 2y = 12.............equation (2)
In elimination method, we need to manipulate the equations in such manner that one of the variables gets eliminated and only one variable remains.
So multiplying equation (2) by 3 we get
3x + 6y = 36
Now subtracting the above equation from equation (1) we get-
3x + 4y - 3x - 6y = 30 - 36
or -2y = -6
or y = 3
Putting the value of y in equation (1) , we get
3x + 4*3 = 30
or 3x = 30-12= 18
or x= 6
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